(1/2)^13= 0.000122070312
Should the TSX close today with a gain, and do it again tomorrow which would not be unusual given that it is a Friday, we will have 13 (a Fibonacci #) days with gains in a row, which looks like this;
Again assuming a roughly 50-50 chance each day for winning or losing, the chances of this happening, at the outset, is 1/2 to the power of 13 or a little more than 1 chance in 10,000. As there are 220 working days this is equivalent to once every 45+ years. According to BNN the last time this happened was in 1985, 29 years ago.
The TSX is metric, it loves tranches of about 1000 points. To do that we need to go to 14,450, another 250 points , give or take. The high on the 7th of March 2011 was 14,329 intraday, just 131 points away. As one commentator observed, even Pavlov could not have trained his dogs this well.